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Call python function from lua #68

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Call python function from lua#68

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@Martmists-GH
Martmists-GH
opened on May 29, 2019

Is there a way to call a python function from Lua? I've tried the following:

-- main.lua
py = require "python"
my_lib = py.import "my_lib"
print(my_lib.test)  -- nil, so I can't call it.
# my_lib.py
def test():
    return 10

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  1. greatwolf commented on May 29, 2019

    @greatwolf
    greatwolf
    on May 29, 2019
    Collaborator

    The handle to the module is returned by py.import so you have to access it through that. For example

    local py = require "python"
local mylib = py.import "my_lib"
print(mylib.test)
mylib.test()      --> should return 10.0

  2. Martmists-GH commented on May 29, 2019

    @Martmists-GH
    Martmists-GH
    on May 29, 2019
    Author

    when doing that I simply get

    main.lua:4: attempt to call field 'test' (a nil value)

    I'm using Lua 5.1 and Python 3.7, both x64

  3. greatwolf commented on May 30, 2019

    @greatwolf
    greatwolf
    on May 30, 2019
    Collaborator

    I just tested this on Lua 5.3 with Python 3.3 32-bit but I can't reproduce the error. What's the lua and python script that's producing that error?

  4. Martmists-GH commented on May 30, 2019

    @Martmists-GH
    Martmists-GH
    on May 30, 2019
    Author

    Literally the code in my initial post is causing this. I don't think I modified any files before building either. (Aside from marking the luaopen_python as __declspec(dllexport) to export the function on windows)

  5. greatwolf commented on May 30, 2019

    @greatwolf
    greatwolf
    on May 30, 2019
    Collaborator

    What does it show when you print(my_lib)?

  6. m32 commented on Jun 3, 2026

    @m32
    m32
    on Jun 3, 2026

    @Martmists-GH sys.path does not include current directory

    py = require "python"
    py.execute "import sys; sys.path.insert(1, '.')"
    ....

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